C1=Cc2nc1c(CCCCC[n+]1ccccc1)c1ccc([nH]1)c(CCCCC[n+]1ccccc1)c1nc(c(CCCCC[n+]3ccccc3)c3ccc([nH]3)c2CCCCC[n+]2ccccc2)C=C1    mol36993